Web1−s2t = x2y2 4(y −x)2 −xy(y −2x). (c) The projection of the initial curve is the set of point {(s,2s)} on the (x,y)-plane. This is the line y = 2x. The point (1,2,1) on the initial curve … WebJan 31, 2024 · Observe that the characteristic line of the PDE, 2u t+ 3u x= 0 is 3t 2x= 0. Thus, the solution is the form of u(t;x) = f(3t 2x) for some di erntiable one variable function f. Note that, by the auxiliary condition, u(0;x) = sin(x) ,we have sin(x) = u(0;x) = f( 2x): Let w= 2x, then f(w) = sin w 2 : Therefore, our solution is u(t;x) = f(3t 2x ...
Solving partial differential equations (PDEs) - University of …
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Solving Partial Differential Equations in R SpringerLink
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